Question

When a series of RLC circuit is subjected to 48V Vr=15V and Vl is 22V what is the voltage across the capacitor

Answer 1

$V = \sqrt{V_r^2+(V_c – 22)^2}$

$48 = \sqrt{15^2+(V_c – 22)^2}$

$48^2 = 15^2 + (V_c – 22)^2$

$V_c – 22 = 45.59$

$V_c = 67.6 \;V$