Question

Two cells each having an emf of 1.5v and an internal resistance of 2 ohms are connected in parallel. Find the current in each case when the cells are connected to a 1 ohm’s resister

Answer 1

Current from one cell

$\Epsilon=I \times R_{c}+I \times R$

$I=\frac{E}{R_{c}+R}=\frac{1.5}{2+1}=0.5A$

Current from second cell is the same. They are both similar.

Current in resistor (summ of currents from two cells):

$I_{r}=I_{1}+I_{2}=0.5+0.5=1A$