Answer to Question #140991 in Electric Circuits for FFFFF

Question #140991
. A mixture of water and sulphuric acid deviates negatively from Raoult’s law. i) State Raoult’s law. ii) What do you understand by negative deviation from Raoult’s law? iii) Explain how a mixture of benzene and ethanol deviate from Raoult’s law. iv) Give one property of mixtures of liquids that could lead to the mixture obeying Raoult’s law
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Expert's answer
2020-10-30T13:13:20-0400

(i) Raoult’s law states that, the partial vapour pressure of each component of an ideal mixture of liquids is equal to the vapour pressure of the pure component multiplied by its mole fraction in the mixture.

(ii) Negative deviation from Raoult's law occurs when the vapour pressure of a mixture is below the value expected from Raoult's law. It arise when the forces between the particles in the mixture becomes stronger than the mean of the forces between the particles in the pure liquids.

(iii) A mixture of benzene and ethanol deviation from Raoult's law in a way that the vapour pressure of the mixture is below the value expected from Raoult's law. This arise when the forces between the benzene and ethanol particles in the mixture becomes stronger than the mean of the forces between the particles in the pure liquids.

(iv) the liquids forming the mixture should be closely similar to each other and this makes the mixture to obey Raoult's law.


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