Question

when a conductor carrying 2.5x10-3 C is discharged to earth, a current of 4mA is needed. How long does the discharge take?

Answer 1

Solution

Current is given by

$I=\frac{q}{t}$

Time taken to discharge

$t=\frac{q}{I}$

$t=\frac{2.5\times10^{-3}}{4\times10^{-3}}$

$t=0.62sec$

Therefore time taken to discharge is 0.62s.