when a conductor carrying 2.5x10-3 C is discharged to earth, a current of 4mA is needed. How long does the discharge take?
Solution
Current is given by
"I=\\frac{q}{t}"
Time taken to discharge
"t=\\frac{q}{I}"
"t=\\frac{2.5\\times10^{-3}}{4\\times10^{-3}}"
"t=0.62sec"
Therefore time taken to discharge is 0.62s.
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