let m be the mass of the body and h be the height it reaches.
Applying the law of conservation of energy we have,
−GMmR+12mvo2=−GMmR+h+0-\frac{GMm}{R}+\frac{1}{2}mv_{o}^{2}=-\frac{GMm}{R+h}+0−RGMm+21mvo2=−R+hGMm+0
GMR+h=2GM−vO2R2R\frac{GM}{R+h}=\frac{2GM-v_{O}^{2}R}{2R}R+hGM=2R2GM−vO2R
cross multiplying and rearranging,
h=Rvo22gR−vo2h=\frac{Rv_{o}^{2}}{2gR-v_{o}^{2}}h=2gR−vo2Rvo2
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