Question

A photon is emitted when a hydrogen atom undergoes a transition from the n=5 state to the n=3 state. Calculate (a) the energy in eV (b) the wavelength (c) the frequency of the emitted photon

Answer 1

Solution

a) energy in case of Hydogen atom is by

$E=13.6 (\frac {1}{n_2^2}-\frac {1}{n_1^2}) eV$

Here$\space n_1=5\space \space n_2=3$ so energy is given by

$E=13.6 (\frac {1}{9}-\frac {1}{25}) eV$

$E=0.98eV$

b) wavelength to corresponding energy is given by

$E=\frac{hc}{\lambda}$

$\lambda=\frac{hc}{E}$

By putting the value of h, c, E

Wavelength becomes

$\lambda=12.63\times10^{-7}m$

c) now frequency is given by

$\upsilon=\frac{E}{h}$

Now putting the value of E and h

Frequency is given by

$\upsilon=0.24\times10^{15} Hz$