The Young's modulus can be obtained as
"E=\\dfrac{F\/S} {\\Delta l\/l}," where F is the force exerted on wire, namely F=mg, S is the area of the wire section, "\\Delta l\/l = 0.1\\%=10^{-3}."
Therefore,
"E=\\dfrac{mg\/(\\pi r^2)}{10^{-3}}=\\dfrac {1\\,\\text{kg}\\cdot9.81\\,\\text{N\/m}\/(\\pi (2\\cdot10^{-4}\\,\\text{m})^2)}{10^{-3}}= 7.8\\cdot10^{10}\\,\\text{Pa}=78\\,\\text{GPa}"
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