A very small ball has a mass of 5.00 x 1023 kg and a charge of 4.00C. What magnitude electric field directed upward will balance the weight of the ball so that the ball is suspended motionless above the ground?
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Expert's answer
2020-11-09T10:00:36-0500
As "F=Eq" and "F=mg" hence "E=mg\/q" then "E=5.00\\sdot10^{-23}\/4\\approx12.3\\sdot10^{-23}V\/m" , where "E" is the magnitude electric field
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