Answer to Question #138532 in Electric Circuits for Jayshree

Question

an amplifier's open circuit output voltage is 10V peak to peak. if when a 10KΩ load is connected the output voltage drops to 8V peak to peak determine the amplifier's output resistance

Answer 1

Since the voltage dropped from $10 V$ to $8 V$ , therefore, the voltage $2 V$ at the new load, therefore the current at the load $I =\frac {U _ {R}} {R} =\frac {2} {10 ^ 4} = 0.0002$ A.

Therefore, resistor resistance $R_{amplifier}=\frac{U_{output}}{I}=\frac{8}{0.0002}=40$ K$\Omega$.