Since the potential "\\phi =\\frac W q" , where "W" is energy and "q" is charge, the voltage "U=\u2206\\phi=\\frac A q" , where "A" is work, a work is equal to "A=q\\times E \\times \u2206r" , from this follows that
"E=\\frac {\u2206\\phi}{\u2206r}" .
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