Since the potential ϕ=Wq\phi =\frac W qϕ=qW , where WWW is energy and qqq is charge, the voltage U=∆ϕ=AqU=∆\phi=\frac A qU=∆ϕ=qA , where AAA is work, a work is equal to A=q×E×∆rA=q\times E \times ∆rA=q×E×∆r , from this follows that
E=∆ϕ∆rE=\frac {∆\phi}{∆r}E=∆r∆ϕ .
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