Since the circuit voltage is equal to the sum of the drop voltage and the collector voltage, Vc=Vcc−Rc , where Vc is the collector voltage, therefore
Vc=12−1,2=10.8 V, since the current voltage falls to the base, therefore, according to the law of Oma Ib=RbRc , and since Ic=Ib×β ; Ic=RbRc×β=47×1031,2×200≈0.051 A.
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