Initialy we have base bias circuit with given quantities as
RB=15kΩ,Rc=100Ω,Vcc=9V ,β at 25°C = 110
Since the given circuit is a base bias circuit then
Vcc=IB×RB
9=IB×15
IB=0.6mA
Case 1: At 0°C
β reduce by 50%
so It will became 2β
Using formula of current gain we have,
2β=IBIc
IC=IB×2110
=0.6×55
=33mA=0.033A
Now using the equation
VCE=VCC−ICRC
=9−0.033×100
=9-3.3
=5.7V
Case 2: At 25°C
β=IBIc
Ic=110×0.6
=66mA=0.066A
Again using the equation,
VCE=VCC−ICRC
= 9−.066×100
=9-6.6
=2.7V
Case 3: At 70°C
β increase by 70%
i.e. β will became β+10075β
i.e.47β
using
47β=IBIc
Ic=IB×47×110
=0.6×7×27.5
=115.5ma=0.1155A
Again using,
VCE=VCC−ICRC
=9−0.1155×100
=9-11.55
=−2.55V
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