Answer to Question #136480 in Electric Circuits for Sulfi

Question

1gm ice mixed with 1gm steam find final temperature of mixture

Answer 1

Heat required to melt 1g of ice,

$Q_1 = mL = 1 \times 80 = 80 cal$

Heat required by 1g of water to boil from $0^{\circ} C$ at $100^{\circ} C$ ,

$Q_2 = ms\Delta T = 1 \times1(100-0) = 100 cal$

Total heat required for 1g of ice to boil,

$Q = Q_1 +Q_2 = 80+100=180 cal$

Heat with 1g ice to condense 1g of water at $100^{\circ} C$ ,

$Q' = mL = 1 \times 536 = 536 cal$

Since total steam will not be condensed hence final temperature of the system will be $100^{\circ} C$