Question

A conductor has a conductance of 50μS. What is its resistance?

Answer 1

solution

conductance(G)=$50\mu S$

$=50\times10^{-6}S$

so

resistance(R)=$\frac{1}{G}$

$then\\R=\frac{1}{50\times10^{-6}}\\R=2\times10^4\Omega$

so resistance is $2\times 10^4\Omega$ .