in RC coupled amplifier the battery voltage is 16V and collector load Rc=4kΩ. its required to set the operating point at Ic=1mA , VCE= 10V by potential divider method. if VBE= 0.2V and I1 = 10IB ẞ= 100 find various circuit values.
Given
"I_c=1mA,V_{ce}=10 V,R_c=4K\\Omega, \\beta=100,V_{BE}=0.2V"
Battery voltage "V_{BB}=16 V"
Using
"V_{CE}=V_{CC}-I_cR_c"
"10=V_{CC}-1\\times 4"
"V_{cc}=14 V"
we know
"\\beta=\\frac{I_c}{I_b}"
"I_b=\\frac{1}{100}"
=0.01mA
using
"V_{BE}=V_{BB}-I_bR_b"
"0.2=16-0.01R_b"
so "R_b=\\frac{15.8}{0.01}"
="1580 K\\Omega"
"I_E=I_b+I_c"
=0.01+1
=1.01mA
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