Question

in RC coupled amplifier the battery voltage is 16V and collector load Rc=4kΩ. its required to set the operating point at Ic=1mA , VCE= 10V by potential divider method. if VBE= 0.2V and I1 = 10IB ẞ= 100 find various circuit values. 

Answer 1

Given

$I_c=1mA,V_{ce}=10 V,R_c=4K\Omega, \beta=100,V_{BE}=0.2V$

Battery voltage $V_{BB}=16 V$

Using

$V_{CE}=V_{CC}-I_cR_c$

$10=V_{CC}-1\times 4$

$V_{cc}=14 V$

we know

$\beta=\frac{I_c}{I_b}$

$I_b=\frac{1}{100}$

=0.01mA

using

$V_{BE}=V_{BB}-I_bR_b$

$0.2=16-0.01R_b$

so $R_b=\frac{15.8}{0.01}$

=$1580 K\Omega$

$I_E=I_b+I_c$

=0.01+1

=1.01mA