A battery of electric motive force of 24 volt internal resistance of 1 ohms connected to a resistor of 32 ohms.what is the current of the battery?
solution
given data
electric motive force(E)=24V
resistance of battery(r)=1ohm
connected resistor(R)=32 ohm
total resistance (Req)=r+R
so
"R_{eq}=1+32\\\\=33\\Omega"
then
by ohm law
"I=\\frac{E}{R_{eq}}"
"I=\\frac{24}{33}\\\\I=0.72A"
so current of battery is 0.72 A .
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