Answer to Question #135352 in Electric Circuits for havefun7741

Question

question in photo

[img]https://upload.cc/i1/2020/09/26/8ZYdLA.jpg[/img]

Answer 1

a) Number of Nodes in the circuit=3

b)kcl equation is given by

$\frac{V_1-0}{4}+\frac{V_1-V_2}{5}-1=0$

$\frac{V_2-0}{3}+\frac{V_2-V_1}{5}-2=0$

C)On solving the above equation and putting V$_1=-6I_x$

We get V$_2=-10 volts$

V$_1=-13.32 volts$

d)Current $I_x=\frac{V_1-V_2}{5}$

=$\frac{140}{63}$ =2.22A

e)Power dissipated in 3$\Omega=\frac{V^2}{R}$

=$\frac{100}{3}$

=33.33 Watt