Answer to Question #134668 in Electric Circuits for MAX

Question #134668
An LED operates at 1.5 V and 5 mA in forward bias. Assuming an 80% external
efficiency of the LED, how many photons are emitted per second?
1
Expert's answer
2020-09-28T08:10:45-0400

Pin=ηextiehfP_{in} = η_{ext}\frac{i}{e}hf

Number of photons =Pinhf=ηextie= \frac{P_{in}}{hf} = η_{ext}\frac{i}{e}

Number of photons =0.8×5×1031.6×1019= 0.8 \times \frac{5 \times 10^{-3}}{1.6 \times 10^{-19}}

Number of photons =2.5×1016= 2.5 \times 10^{16}


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