Let's find the current in immersion heater. According to Ohm's law:
V=IR ⇒ I=VR\displaystyle V = IR \; \; \Rightarrow \; \; I = \frac{V}{R}V=IR⇒I=RV
The power output is
P=VI=V2R=240220=28 800 W=28.8 kW\displaystyle P = VI = \frac{V^2}{R} = \frac{240^2}{20}= 28\;800 \; \textrm{W} = 28.8 \; \textrm{kW}P=VI=RV2=202402=28800W=28.8kW
Answer: 28.828.828.8 kW
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