According to the Ohm's law,
V=IR⇒ I=VR=10 V5 Ω=2 A.\displaystyle V= IR \Rightarrow \; I = \frac{V}{R} = \frac{10 \, V}{5 \, \Omega} = 2\, A.V=IR⇒I=RV=5Ω10V=2A.
Answer: 2 A.
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