Given
Length of coil is l=2.2ml=2.2 ml=2.2m
Magnetic field at the center of the solenoid is B=0.4TB=0.4 TB=0.4T
The energy stored in the solenoid is
U=B2Al2μ0=(0.4)2(π(0.45)2)(2.2)2(4π×10−7)U=\frac{B^2Al}{2\mu_0}=\frac{(0.4)^2(\pi(0.45)^2)(2.2)}{2(4\pi\times10^{-7} )}U=2μ0B2Al=2(4π×10−7)(0.4)2(π(0.45)2)(2.2)
=8.91×104T=8.91\times10^4 T=8.91×104T
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