Question

The 1000-turn, 0.4 m diameter coil of a generator is rotated at 120 rpm in a 0.038 T field. In order
to be able to measure the emf induced by the generator up to the maximum, a galvanometer of
10

Answer 1

As per the given question,

Number of turn$(N)=1000$

Diameter of the coil $(d)=0.4m$

Frequency of the rotation of the coil $(\omega)=2\pi \times 120\times \frac{1}{60} =4\pi Hz$

Magnetic field$(B)=0.038T$

$E=NBA\omega$

Now, substituting the values in equation,

$E=1000\times 0.038\times \pi (\frac{0.4}{2})^2\times 4\pi Volt$

$=1000\times 0.038\times \pi\times 0.04 \times 4\pi Volt$

$=19.1 Volt$