Question

find the force of an attraction between two equal but opposite charges of 2*10^-6C if the distance between them is 25cm

Answer 1

Given points are

Charge is $Q=2*10^{-6} C$

Distance between them is $r=0.25 m$

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The attraction force between the two charges is

$F=\frac{kQ^2}{r^2}$

$=\frac{(9*10^9)(2*10^{-6})^2}{(0.25)^2}$

$=0.576 N$