Question

What will be the current if 3 Ω and 6 Ω resistors are connected in parallel and 2 V potential difference is applied?

Answer 1

R_equivalent=$\frac{R_1R_2}{R_1+R_2}=\frac{6\times3}{6+3}=2$

$i=\frac{V}{R}=\frac22=1$