Question

. A battery of e.m.f 6.0 V passes a current of 0.3 A through a torch bulb for 5 minutes. How much energy is transferred from the cell?
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Answer 1

Electric energy can be calculated according to:

$$A=I*U*t$$

For our case I = 0.3 A, U = 6 V, t = 5 minutes = 5*60 = 300 seconds.

So we have:

$A=0.3A*6V*300sec=540J$

Answer: 540J of energy was transferred from the cell.