Question

A charge q1, = 5.0μc is placed 30cm to the west of another charge q2=12μc. What is the force exerted by the positive charge on the negative charge?

Answer 1

Force=$\frac{kq_1q_2}{r^2}=\frac{9\times10^9\times5\times10^{-6}\times12\times10^{-6}}{0.3^2}=6\ newton$