Question #121281
What is the right option of 179?
http://prntscr.com/swe1fz
1
Expert's answer
2020-06-10T18:25:14-0400

Explanations & Calculations


  • Electrical resistance of a material is given by R = ρlA\frac{\rho l}{A}
  • Therefore a relationship for the given wire could be written using that as follows.

36=ρ×lA=kl(ρAis constant)\qquad\qquad \begin{aligned} \small 36 &= \frac{\rho \times l}{A} = \small kl \cdots(\frac{\rho}{A} \,\,\text{is constant}) \end{aligned}

  • This means the resistance of a segment of this wire depends on the length of the segment considered.


  • Therefore, resistance of the 300 segment (R1)

R1=k×30l360=112kl=3Ω\qquad\qquad \begin{aligned} \small R_1 &= \small k\times \frac{30l}{360} = \small \frac{1}{12}kl = 3\Omega\\ \end{aligned}

  • Resistance of the remaining segment is (R2 )

R2=1112kl=36R1=33Ω\qquad\qquad \begin{aligned} \small R_2 &= \small \frac{11}{12}kl = \small 36-R_1 = 33 \Omega \end{aligned}

  • About AB, these two wires are in a parallel combination which equivalent to (Re)

Re=3Ω×33Ω3Ω+33Ω=2.75Ω\qquad\qquad \begin{aligned} \small R_e &= \small \frac{3\Omega\times33\Omega}{3\Omega+33\Omega}\\ &= \small \bold{2.75 \Omega} \end{aligned}


  • Answer (A)

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