Explanations & Calculations
- Electrical resistance of a material is given by R = Aρl
- Therefore a relationship for the given wire could be written using that as follows.
36=Aρ×l=kl⋯(Aρis constant)
- This means the resistance of a segment of this wire depends on the length of the segment considered.
- Therefore, resistance of the 300 segment (R1)
R1=k×36030l=121kl=3Ω
- Resistance of the remaining segment is (R2 )
R2=1211kl=36−R1=33Ω
- About AB, these two wires are in a parallel combination which equivalent to (Re)
Re=3Ω+33Ω3Ω×33Ω=2.75Ω
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