Question #121021

1)

O

B 3 cm

+2 μC

Figure 1

5 cm

A -2μC 4 cm

There are two charged spheres are located like shown in figure above. Coulomb’s constant

Expert's answer

As per the question,

It is incomplete question, so i am taking assumption that here we have to find the force

Let there is two charged sphere A and B, and distance between OA is =5cm

distance between OB=4cm and AB = 3cm

Charge on A is =−2μC=-2\mu C

Charge on B is =2μC=2\mu C

force between two charges is (F)=q1q24πϵor2(F)=\frac{q_1 q_2}{4\pi \epsilon_o r^2}

Now, substituting the values,

⇒F=−9×109×2×2(3×10−2)2N\Rightarrow F=-\frac{9\times 10^{9}\times2\times 2}{(3\times 10^{-2})^2}N

⇒F=−4×10−13N\Rightarrow F=-4\times 10^{-13}N

Here negative sign indicates that the force between these two charges is attraction force.


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