Answer to Question #118780 in Electric Circuits for Ginger-Eke Ceejay

Question

Two batteries P and Q each of Emf 8 V and 3 V have internal resistance of 2 Ω and 4 Ω respectively.
Calculate the values of the current through the circuit.

Answer 1

Assume that the elements are connected in series. So,

total $e.m.f.=8+3=11 V$

total internal resistance $r=2+4=6\Omega$

current $I=11/6=1.83A$.