Question #118780
Two batteries P and Q each of Emf 8 V and 3 V have internal resistance of 2 Ω and 4 Ω respectively.
Calculate the values of the current through the circuit.
1
Expert's answer
2020-05-29T09:46:37-0400

Assume that the elements are connected in series. So,


total e.m.f.=8+3=11Ve.m.f.=8+3=11 V


total internal resistance r=2+4=6Ωr=2+4=6\Omega


current I=11/6=1.83AI=11/6=1.83A.




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