"L=1.0m\\\\S=2\\times10^{-7}m^2\\\\R=0.1\\Omega\\\\\\rho-?\\\\solution:\\\\R=\\rho\\times \\frac{L}{S} \\Rightarrow\\rho=\\frac{R\\times S}{L};\\\\\\rho=\\frac{0.1\\times2\\times10^{-7} }{1}=0.2\\times 10^{-7}\\Omega\\times m.\\\\Answer:\\;the \\;electrical\\; conductivity\\\\ of \\;the\\; wire\\;equals\\;0.2\\times 10^{-7}\\Omega\\times m."
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