Question #118453

Calculate the length of a constant wire of cross sectional areas 4π x 10^8m and resistivity 1.1 x 10^-6Ωm required to construct a standard resistor of resistance 21Ω (take π=22/7)

Expert's answer

The resistance in terms of conductor length LL, area AA , and resistivity ρ\rho is


R=ρLA→ L=RAρ=21⋅4π⋅1081.1⋅10−6=2.4⋅1016 m.R=\frac{\rho L}{A}\rightarrow \\ \space\\L=\frac{RA}{\rho}=\frac{21\cdot4π \cdot10^8 }{1.1 \cdot 10^{-6}}=2.4\cdot10^{16}\text{ m}.

Longer than the distance from the Sun to Saturn!


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