Answer to Question #116930 in Electric Circuits for James

Question #116930

The r.m.s value of an alternating voltage is 14V. What is the value of the peak voltage?

Expert's answer

As "V_{r.m.s}=\\frac{V_{peac}}{\\sqrt2}" hence "V_{peac}=\\sqrt2\\sdot V{r.m.s}\\approx1.41\\sdot14\\approx19.7V"

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