Question #116930
The r.m.s value of an alternating voltage is 14V. What is the value of the peak voltage?
1
Expert's answer
2020-05-19T10:52:15-0400

As Vr.m.s=Vpeac2V_{r.m.s}=\frac{V_{peac}}{\sqrt2} hence Vpeac=2⋅Vr.m.s≈1.41⋅14≈19.7VV_{peac}=\sqrt2\sdot V{r.m.s}\approx1.41\sdot14\approx19.7V


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