Question

Plates of area A are arranged as shown. The distance between them is d. Find the net capacitance

Answer 1

We know that

$$electric\ field ,\ E=\frac{\sigma}{ \epsilon_0}=\frac{q}{A\epsilon_0}\\voltage=V=Ed\\C=\frac{q}{V}$$

putting all values

we get

$$C=\frac{AE\epsilon_0}{Ed}=\frac{\epsilon_0A}{d}$$