R=R1+R2;I=UR1+R2;R2=UI−R1;R2=1.50.25−1;R2=5ΩR=R_1+R_2;I=\frac{U}{R_1+R_2};\\R_2=\frac{U}{I}-R_1;R_2=\frac{1.5}{0.25}-1;\\R_2=5\OmegaR=R1+R2;I=R1+R2U;R2=IU−R1;R2=0.251.5−1;R2=5Ω
Answer:R2=5ΩR_2=5\OmegaR2=5Ω
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