The potential of the point charge is:
"\\varphi = k\\dfrac{q}{r}" ,
where "q" is the charge, "r" is the distance from charge to the point of measurement and "k = 9\u00d710^9 N\u22c5m^2\u22c5C^{\u22122}" is the Coulomb's constant. Express "r" from this formula ans substitute numerical values:
"r = k\\dfrac{q}{\\varphi} = 9\\cdot 10^9 \\dfrac{66\\cdot 10^{-9}}{291} = 2.04 m".
Answer. r = 2.04 m.
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