As per the given question,
Let the charge of the cathode beam is Q, mass of the charge is m, it is passing in the magnetic field B and electric field E, in the potential difference V. let the radius of the cathode ray is R,
Now, applying the conservation of energy,
"QV=\\dfrac{mv^2}{2}------(i)"
Now,
"\\Rightarrow QvB=QE"
"\\Rightarrow v=\\dfrac{E}{B}------(ii)"
now substituting the value of v in equation (i) from equation (ii)
"QV=\\dfrac{mE^2}{2B^2}"
"\\Rightarrow \\dfrac{Q}{m}=\\dfrac{E^2}{2B^2V}"
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