Question #113113
Determine the power dissipated when a current of 10Ma flows through an appliance having a resistance of 8kΩ
1
Expert's answer
2020-05-04T12:49:53-0400

I=107AI=10^7A

R=8×103OhmR=8\times10^3 Ohm

Power dissipated is P=I2R=8×1017WP=I^2R=8\times10^{17} W


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