Question #112651
Determine the power dissipated when a current of 10Ma flows through an appliance having a resistance of 8kΩ
1
Expert's answer
2020-04-30T10:42:42-0400

As per the given question,

Current in the appliances (i)=10×106A(i)=10\times 10^6A

Resistance of the appliances (R)=8×103Ω(R)=8\times 10^3 \Omega

We know that, power dissipation in the appliances (P)=i2R(P)=i^2R

P=(10×106)2×8000=8×1017wattP=(10\times 10^6)^2\times8000=8\times 10^{17}watt


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