As per the given question,
Current in the appliances "(i)=10\\times 10^6A"
Resistance of the appliances "(R)=8\\times 10^3 \\Omega"
We know that, power dissipation in the appliances "(P)=i^2R"
"P=(10\\times 10^6)^2\\times8000=8\\times 10^{17}watt"
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