Question #112637
A 12µF capacitor is required to store 4J of energy. Find the p.d to which the capacitor must be charged.
1
Expert's answer
2020-04-28T09:45:34-0400

E=4E=4 J

C=12×1012μFC=12\times 10^{-12} \mu F

E=CU22E={\frac {CU^2} 2}

U=2EC=8.2×105VU=\sqrt{{\frac {2E} C}}=8.2\times10^5 V


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