Question

what is the critical angle for a material of refractive index square root 2

Answer 1

what is the critical angle for a material of refractive index square root 2

# Solution

We are given:

$$n _ {1} = \sqrt {2}$$

For detailed information about critical angle see

http://en.wikipedia.org/wiki/Critical_angle (optics)#Critical_angle

Assume given material -air boundary;

For air:

$$n _ {2} = n _ {\text {a i r}} = 1$$

Thus:

$$\Theta_ {\text {c r i t i c a l}} = \arcsin \left(\frac {n _ {2}}{n _ {1}}\right) = \arcsin \left(\frac {1}{\sqrt {2}}\right) = 4 5 ^ {\circ} = \frac {\pi}{4} r a d$$

Answer: $45^{\circ}$

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