First two resistors will be in parallel. So,"\\frac{1}{r}+\\frac{1}{r}=\\frac{2}{r}"
Now this resistor and the third resistor will be connected in series. So,
"\\frac{r}{2}+r=\\frac{3r}{2}"
Hence, the net resistance will be equal to "\\frac{3r}{2}=6ohm"
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