Answer to Question #106404 in Electric Circuits for Muhammad saad bhatti

Question

An air filled parallel plate capacitor has a capacitrence of 1 pF.The plate separation is then doubled and a wax dielectric is inserted completely filling the separation

Answer 1

$C=\frac{kA\epsilon}{d}$

So we can see that Capacitance is inversely proportional to d which is plate separation and is directly proportional to k which is the dielectric constant of the medium

So if the plate separation is doubled then the capacitance will get halved and as the capacitor is filled with dielectric then the capacitance will get multiplied by k

Hence final capacitance will be $\frac{k\times1}{2}$