Question

A surface area measuring 0.0024m^2 is parallel to an electric field with a magnitude of 5×〖10〗^4 N/C. Calculate the flux of the surface.

Answer 1

$\Phi=B\cdot S\cdot \cos\alpha$ .

According to the condition of the problem, the surface is parallel to the electric field lines. So, $\alpha=90°$. We have

$\Phi=5\cdot10^4\cdot 0.0024\cdot\cos90°=0.$