Question #103537
Fine the impedance of a series RLC circuit if the inductive reactance, capacitive reactance and resistance are 184 ohms, 144 ohms and 30 ohms respectively. Also calculate the phase angle between voltage and current
1
Expert's answer
2020-02-24T10:20:54-0500

When connected in series, the component impedances are added together

(1) Z=R+iwL+1iwCZ=R+iw\cdot L+ \frac{1}{iw \cdot C}

To determine the phase angle between voltage and current, impedance should be represented in the Euler's form

Z=Zeiarg(Z)Z=|Z|\cdot e^{iarg(Z)}

Determine first real and imaginary parts of the impedance (1) Z=R+iXZ=R+iX . We can see reactanceX=Lw1CwX=Lw-\frac{1}{Cw} . Thus

Z=R2+X2=R2+(Lw1/Cw)2=302+(184144)2=50Ω|Z|=\sqrt{R^2+X^2}=\sqrt{R^2+(Lw-1/Cw)^2}=\sqrt{30^2+(184-144)^2}=50\Omega


arg(Z)=arctan(XR)=arctan(Lw1CwR)=arctan(4030)=53°arg(Z)=arctan(\frac{X}{R})=arctan(\frac{Lw-\frac{1}{Cw}}{R})=arctan(\frac{40}{30})=53\degree


Answer: The phase angle between voltage and current θ=53°{\displaystyle \theta } =53\degree


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