Question #103537

Fine the impedance of a series RLC circuit if the inductive reactance, capacitive reactance and resistance are 184 ohms, 144 ohms and 30 ohms respectively. Also calculate the phase angle between voltage and current

Expert's answer

When connected in series, the component impedances are added together

(1) Z=R+iwL+1iwCZ=R+iw\cdot L+ \frac{1}{iw \cdot C}

To determine the phase angle between voltage and current, impedance should be represented in the Euler's form

Z=Zeiarg(Z)Z=|Z|\cdot e^{iarg(Z)}

Determine first real and imaginary parts of the impedance (1) Z=R+iXZ=R+iX . We can see reactanceX=Lw1CwX=Lw-\frac{1}{Cw} . Thus

Z=R2+X2=R2+(Lw1/Cw)2=302+(184144)2=50Ω|Z|=\sqrt{R^2+X^2}=\sqrt{R^2+(Lw-1/Cw)^2}=\sqrt{30^2+(184-144)^2}=50\Omega


arg(Z)=arctan(XR)=arctan(Lw1CwR)=arctan(4030)=53°arg(Z)=arctan(\frac{X}{R})=arctan(\frac{Lw-\frac{1}{Cw}}{R})=arctan(\frac{40}{30})=53\degree


Answer: The phase angle between voltage and current θ=53°{\displaystyle \theta } =53\degree


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