When connected in series, the component impedances are added together
(1) "Z=R+iw\\cdot L+ \\frac{1}{iw \\cdot C}"
To determine the phase angle between voltage and current, impedance should be represented in the Euler's form
"Z=|Z|\\cdot e^{iarg(Z)}"
Determine first real and imaginary parts of the impedance (1) "Z=R+iX" . We can see reactance"X=Lw-\\frac{1}{Cw}" . Thus
"|Z|=\\sqrt{R^2+X^2}=\\sqrt{R^2+(Lw-1\/Cw)^2}=\\sqrt{30^2+(184-144)^2}=50\\Omega"
"arg(Z)=arctan(\\frac{X}{R})=arctan(\\frac{Lw-\\frac{1}{Cw}}{R})=arctan(\\frac{40}{30})=53\\degree"
Answer: The phase angle between voltage and current "{\\displaystyle \\theta } =53\\degree"
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