Question #101926

A bulb is designed to work with peak voltage 45V and period 28ms. It has resistance 120 Ohms and is in series with a 5.1 kiloohms resistor and an AC power supply.

Complete the following:

a) Sketch and label the circuit diagram

b) The frequency of the power supply

c) The peak current through the bulb

d) The voltage RMS of the power supply

Expert's answer

a)



b) We are given time period 28 ms

frequency= 1/time period = 1/0.028 = 35.7 Hz


c) peak current = peak voltage /resistance = 45/120 = 0.375 ampere


d) RMS voltage = Peak voltage/2\sqrt2 = 45/2\sqrt2 volts



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