Question #99095

in a damped oscillator m = 250g , k=85N/m, and b = 0.070kg/s. in how many periods of oscillation will the mechanical energy of the oscillator drop to one-half of this initial value?

Expert's answer

E(t)=E0ebtm=0.5E0E(t)=E_0e^{-\frac{bt}{m}}=0.5E_0

t=mln2b=0.25ln20.07=2.4755 st=\frac{m\ln{2}}{b}=\frac{0.25\ln{2}}{0.07}=2.4755\ s

The period:

T=2πmk=2π0.2585=0.34 sT=2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{0.25}{85}}=0.34\ s

N=tT=2.47550.34=7.3N=\frac{t}{T}=\frac{2.4755}{0.34}=7.3


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