2019-11-20T12:15:53-05:00
in a damped oscillator m = 250g , k=85N/m, and b = 0.070kg/s. in how many periods of oscillation will the mechanical energy of the oscillator drop to one-half of this initial value?
1
2019-11-21T10:04:26-0500
E ( t ) = E 0 e − b t m = 0.5 E 0 E(t)=E_0e^{-\frac{bt}{m}}=0.5E_0 E ( t ) = E 0 e − m b t = 0.5 E 0
t = m ln 2 b = 0.25 ln 2 0.07 = 2.4755 s t=\frac{m\ln{2}}{b}=\frac{0.25\ln{2}}{0.07}=2.4755\ s t = b m ln 2 = 0.07 0.25 ln 2 = 2.4755 s The period:
T = 2 π m k = 2 π 0.25 85 = 0.34 s T=2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{0.25}{85}}=0.34\ s T = 2 π k m = 2 π 85 0.25 = 0.34 s
N = t T = 2.4755 0.34 = 7.3 N=\frac{t}{T}=\frac{2.4755}{0.34}=7.3 N = T t = 0.34 2.4755 = 7.3
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