Question

We fill an entire a 15cm deep glass with kerosene. What is the pressure that the fluid exerts on the bottom of the glass –

Answer 1

Kerosene density is equal to $\rho = 0.81 \text{ g/cm}^3 = 810 \text{ kg/m}^3$

Therefore, pressure on the bottom of the glass

$$p = \rho g h = 810\text{ kg/m}^3 \cdot 9.81\text{ m/s}^2 \cdot 0.15\text{ m} = 1190 \text{ Pa}$$