Answer to Question #96210 in Classical Mechanics for John

Question #96210
Questions in the link
https://eksiup.com/p/zh2525055pgx
1
Expert's answer
2019-10-10T09:43:35-0400

In general case, as the net force is zero:


"{T}_{AB}\\cos\\theta_2=F\\sin\\theta_1""T_{AC}+T_{AB}\\sin\\theta_2=F\\cos\\theta_1"

It has the solution:


"{T}_{AB}=\\frac{F\\sin\\theta_1}{\\cos\\theta_2}"


"T_{AC}=-\\frac{F\\sin\\theta_1}{\\cos\\theta_2}\\sin\\theta_2+F\\cos\\theta_1"

So, for case a):

"{T}_{AB}=\\frac{100*\\sin0^{\\circ}}{\\cos45^{\\circ}}=0N"

"T_{AC}=-0+100\\cos0^{\\circ}=100N"

for case b)



"{T}_{AB}=\\frac{100*\\sin30^{\\circ}}{\\cos60^{\\circ}}=100N"

"T_{AC}=36.6N"


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