Question #95746

A disc rotates about axis its angular velocity w varries with time according to the equation w=at+b initially at t=0 angular velocity 1rad per second and angular position 2rad at t=2sec angular velocity 5rad per sec. Determine angular position and angular acceleration

Expert's answer

w(0)=b=1radsw(0)=b=1\frac{rad}{s}

The angular acceleration:


a=5−12−0=2rads2a=\frac{5-1}{2-0}=2\frac{rad}{s^2}

The angular position:


ϕ=0.5at2+bt+c=t2+t+c\phi=0.5at^2+bt+c=t^2+t+c

ϕ(0)=c=2 rad\phi(0)=c=2\ rad

Thus,


ϕ=t2+t+2\phi=t^2+t+2


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