Question

Question 20
A block of mass 1.8kg is at rest on a smooth horizontal table. The block is connected to a hanging mass of 2kg, by a light inextensible string and frictionless pulley system as shown in Figure 5. The hanging mass is then released from rest. Determine;
(a) The acceleration of the block/hanging mass system (b) The tension in the string.

Answer 1

$A2y=-A1.8x$

$A2y=\frac{\Sigma F}{M}$$;A2y=2\times9.81/3.8$

A_2y=5.16m/s²

Thus A_1.8x=-5.16m/s²

Again,

$A1.8x=\frac{T}{M}$

-5.16=T/3.8

T=19.62kgm/s²