Answer to Question #91707 in Classical Mechanics for Louie

Question #91707
Question 20
A block of mass 1.8kg is at rest on a smooth horizontal table. The block is connected to a hanging mass of 2kg, by a light inextensible string and frictionless pulley system as shown in Figure 5. The hanging mass is then released from rest. Determine;
(a) The acceleration of the block/hanging mass system (b) The tension in the string.
1
Expert's answer
2019-07-23T15:54:17-0400

A2y=A1.8xA2y=-A1.8x

A2y=ΣFMA2y=\frac{\Sigma F}{M};A2y=2×9.81/3.8;A2y=2\times9.81/3.8

A2y=5.16m/s2

Thus A1.8x=-5.16m/s2

Again,

A1.8x=TMA1.8x=\frac{T}{M}

-5.16=T/3.8

T=19.62kgm/s2

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